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QUESTION

Find $\ds\int\frac{x}{x+1}\,dx$.

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ANSWER

$\ds\int\frac{x}{x+1}\,dx=\int\frac{x+1-1}{x+1}\,dx=\int\left(1-\frac{1}{x+1}\right)\,dx
=x-\ln|x+1|+c$




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