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QUESTION Simplify $\ds\frac{x(x^2)^\frac{1}{3}}{x^\frac{1}{2}}$


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ANSWER

$\ds\frac{x(x^2)^\frac{1}{3}}{x^\frac{1}{2}}
=\frac{xx^\frac{2}{3}}{x^\frac{1}{2}}
=x^{1+\frac{2}{3}-\frac{1}{2}} =x^\frac{7}{6}$





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