<html><head><meta name="color-scheme" content="light dark"></head><body><pre style="word-wrap: break-word; white-space: pre-wrap;">\documentclass[a4paper,12pt]{article}
\newcommand\ds{\displaystyle}
\begin{document}

\parindent=0pt

QUESTION

Find the inverse Laplace transform of the function
$\ds\frac{1}{s^2+2s+2}$

\bigskip

ANSWER


$\ds{\cal{L}}^{-1}\left\{\frac{1}{s^2+2s+2}\right\}={\cal{L}}^{-1}\left\{\frac{1}{(s+1)^2+1}\right\}=e^{-t}\sin
(t)$



\end{document}
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